48x^2+48x-72=0

Solution for 48x^2+48x-72=0 equation:

48x^2+48x-72=0

a = 48; b = 48; c = -72;
Δ = b2-4ac
Δ = 482-4·48·(-72)
Δ = 16128
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{16128}=\sqrt{2304*7}=\sqrt{2304}*\sqrt{7}=48\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-48\sqrt{7}}{2*48}=\frac{-48-48\sqrt{7}}{96}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+48\sqrt{7}}{2*48}=\frac{-48+48\sqrt{7}}{96}
$